Choosing elements with Selenium on Instagram

Question

Choosing elements with Selenium on Instagram

Currently, I'm in the process of developing an Instagram bot that will automatically like images by identifying the 'heart element' on the webpage and clicking on it.

Upon inspection, I noticed that the structure of the element looked like this:

<div class="eo2As ">
<section class="ltpMr Slqrh">
<a class="fr66n tiVCN" href="#" role="button">
<span class="Szr5J coreSpriteHeartOpen ">Like</span></a>

The class values remain consistent for all unliked heart elements throughout the page.

This is my current code snippet:

from selenium import webdriver
username = "----"
password = "----" #values from original file

getdriver = ("https://www.instagram.com/accounts/login/")

driver = webdriver.Chrome(r'C:\testDir\chromedriver_win32\chromedriver.exe')
driver.get(getdriver)

driver.find_element_by_xpath("//input[@name='username']").send_keys(username)
driver.find_element_by_xpath("//input[@name='password']").send_keys(password)
driver.find_element_by_xpath("//button[contains(.,'Log in')]").click()

#Everything working fine up to this point

like = driver.find_element_by_css_selector('.Szr5J.coreSpriteHeartOpen')

for x in range(0,len(like)):
    if like[x].is_displayed():
        like[x].click()

However, I keep encountering the following error message:

selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":".Szr5J.coreSpriteHeartOpen"}

I've experimented with different combinations of class names but haven't been able to find a solution yet!

If you have any insights or suggestions, they would be greatly appreciated!

python-3.x selenium selenium-webdriver automation selenium-chromedriver

Answer 1

Answer №1

Consider trying these options:

# The script may be too quick and attempting to locate the element before the page is fully loaded. Using `WebDriverWait` can help with this issue
like = WebDriverWait(driver, 5).until(EC.presence_of_element_located((By.CSS_SELECTOR, '.Szr5J.coreSpriteHeartOpen')))

or:

import time

time.sleep(5) # Pause for 5 seconds after logging into Instagram
like = driver.find_element_by_css_selector('.Szr5J.coreSpriteHeartOpen')

If I understand correctly, you want to find all 'hearts' on the page. In that case, you should use

driver.find_elements_by_css_selector

like so:

# Returns an array of elements found
like = driver.find_elements_by_css_selector('.Szr5J.coreSpriteHeartOpen')

You can then iterate through these elements using a loop.

Here is the complete working code:

username = "----"
password = "----" # These values are from the original file

getdriver = ("https://www.instagram.com/accounts/login/")

driver = webdriver.Chrome(r'C:\testDir\chromedriver_win32\chromedriver.exe')
driver.get(getdriver)

driver.find_element_by_xpath("//input[@name='username']").send_keys(username)
driver.find_element_by_xpath("//input[@name='password']").send_keys(password)
driver.find_element_by_xpath("//button[contains(.,'Log in')]").click()

# Close the popup that appears after login
popup = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, '//div/div/button[contains(., Close)]'))
driver.find_element_by_xpath("//div/div/button[contains(., Close)]").click()

WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.CSS_SELECTOR, '.Szr5J.coreSpriteHeartOpen')))
# Find all 'hearts' on the page
likes = driver.find_elements(By.CSS_SELECTOR, ".Szr5J.coreSpriteHeartOpen")
print(len(likes))
print("WORKS")

for x in range(0,len(likes)):
    if likes[x].is_displayed():
        likes[x].click()
        print(x)

Output:

3
WORKS
0
1
2

Answer 2

Consider trying these options:

# The script may be too quick and attempting to locate the element before the page is fully loaded. Using `WebDriverWait` can help with this issue
like = WebDriverWait(driver, 5).until(EC.presence_of_element_located((By.CSS_SELECTOR, '.Szr5J.coreSpriteHeartOpen')))

or:

import time

time.sleep(5) # Pause for 5 seconds after logging into Instagram
like = driver.find_element_by_css_selector('.Szr5J.coreSpriteHeartOpen')

If I understand correctly, you want to find all 'hearts' on the page. In that case, you should use

driver.find_elements_by_css_selector

like so:

# Returns an array of elements found
like = driver.find_elements_by_css_selector('.Szr5J.coreSpriteHeartOpen')

You can then iterate through these elements using a loop.

Here is the complete working code:

username = "----"
password = "----" # These values are from the original file

getdriver = ("https://www.instagram.com/accounts/login/")

driver = webdriver.Chrome(r'C:\testDir\chromedriver_win32\chromedriver.exe')
driver.get(getdriver)

driver.find_element_by_xpath("//input[@name='username']").send_keys(username)
driver.find_element_by_xpath("//input[@name='password']").send_keys(password)
driver.find_element_by_xpath("//button[contains(.,'Log in')]").click()

# Close the popup that appears after login
popup = WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, '//div/div/button[contains(., Close)]'))
driver.find_element_by_xpath("//div/div/button[contains(., Close)]").click()

WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.CSS_SELECTOR, '.Szr5J.coreSpriteHeartOpen')))
# Find all 'hearts' on the page
likes = driver.find_elements(By.CSS_SELECTOR, ".Szr5J.coreSpriteHeartOpen")
print(len(likes))
print("WORKS")

for x in range(0,len(likes)):
    if likes[x].is_displayed():
        likes[x].click()
        print(x)

Output:

3
WORKS
0
1
2

Choosing elements with Selenium on Instagram

Answer №1

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