Currently, I am developing a web application using Express. My goal is to merge, minify, and serve .js files efficiently. To achieve this, I have created a middleware with the following code:
var fs = require('fs'),
path = require('path'),
uglify = require('uglify-js'),
cache = '',
scriptsDir = path.join(__dirname, '../scripts'),
files = fs.readdirSync(scriptsDir);
// Since the code runs on startup, synchronous read is acceptable
files.forEach(function(fname) {
if (/^.*\.js$/.test(fname)) {
cache += fs.readFileSync(path.join(scriptsDir, fname), 'utf8').toString();
}
});
cache = uglify.minify(cache, { fromString: true }).code;
module.exports = function(req, res, next) {
if (req.url === '/js/all.js')
res.end(cache);
else
next();
};
This middleware should be used as shown below:
app.use(compress());
[...]
app.use(app.router);
app.use(jsMerger); // This is where my middleware is invoked
app.use(express.static(path.join(__dirname, '../public')));
The issue at hand is that the response is not gzipped, and it lacks essential headers such as cache headers and etags. The current response looks like this:
X-Powered-By: Express
Transfer-Encoding: chunked
Date: Wed, 12 Mar 2014 14:04:19 GMT
Connection: keep-alive
I am seeking guidance on how to compress the response effectively. Any insights or suggestions would be greatly appreciated.