I have the beginning, final number, and a list of available values.
start_number = 6001, end_number = 6190
List = [u'6001', u'6005', u'6008', u'6002']
Given this list, I am looking to find the smallest missing value between the start and end numbers. In this case, I am aiming to retrieve the value of 6003
What is the most effective way to accomplish this task using Python?
To efficiently find the first number in a well-defined range that is not in a given list, you can utilize the following approach:
my_set = set(map(int, List))
val = next(i for i in range(start_no, end_no+1) if i not in my_set)
This method eliminates the need to create a new list and iterate through its entire length using min.
For larger lists, converting it to a set can significantly decrease the time required for membership lookup.
Experimenting:
beginning_number = 6001
ending_number =6190
minimum_value = ""
item_list = [u'6001', u'6005', u'6008', u'6002']
for element in range(beginning_number, ending_number+1):
if str(element) not in item_list:
minimum_value = str(element)
break
MODIFY: Using list comprehension.
minimum_value = min([element for element in range(beginning_number, ending_number + 1) if str(element) not in item_list])
Here is an example of a similar code snippet:
start_num = 5211
end_num = 5389
current_num = start_num
num_list = [u'5211', u'5214', u'5220', u'5212']
while str(current_num) in num_list and current_num < end_num:
current_num += 1
if current_num not in num_list:
print "The result is %d" % current_num
else:
print "No missing numbers were found"
To find the smallest number, simply iterate from the beginning to the end. The first number that is not in the list will be the smallest one.
starting_number = 6001
ending_number = 6190
numbers_list = [u'6001', u'6005', u'6008', u'6002']
for num in range(starting_number, ending_number + 1):
if str(num) not in numbers_list:
return num
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