In my coding project, I came across a situation where I needed to write a method in Typescript. This method should allow me to run some checks and, if those conditions are met, return the result of another method. What I want is to pass a method along with its parameters to another method so that it can be executed under certain conditions.
Initially, I tried doing this by implementing the following code (you can check the fiddle here):
function getTheResult(inputVal:number, multiplier:number, subtractor:number):number{
inputVal = inputVal * multiplier - subtractor;
return inputVal;
}
function intermediary(passedFunction:Function, inputVal:number, multiplier:number, subtractor:number, name:string):number{
if(name == 'John')
return -1;
return(passedFunction(inputVal, multiplier, subtractor));
}
console.log(intermediary(getTheResult, 5, 4, 5, 'Mike'));
Although this code works as intended, I wanted to find a way to pass getTheResult(5,4,5) directly to
intermediary(passedFunction:Function, name:string)intermediary() can call any method that I pass to it, regardless of the function's parameters. To better understand, you can refer to this fiddle (available here):
function getTheResult1(inputVal:number, multiplier:number, subtractor:number):number{
inputVal = inputVal * multiplier - subtractor;
return inputVal;
}
function getTheResult2(inputVal:number, dividor:number):number{
inputVal = inputVal / dividor;
return inputVal;
}
function intermediary(passedFunction:Function, name:string):number{
if(name == 'John')
return -1;
return(passedFunction());
}
let myFirstNum:number = intermediary(getTheResult1(2,3,4), 'John');
let mySecondNum:number = intermediary(getTheResult2(2,3), 'Doe');
console.log(myFirstNum);
console.log(mySecondNum);
Can you help me understand how I can achieve this?