Exploring DataFrames with interrows() and writing them out as CSV files with .to_csv:

I am using the following script to perform the following actions:

  • Apply a function to a column in each row of a DataFrame
  • Write the returns from that function into two new columns of a DataFrame
  • Continuously write the DataFrame into a *.csv

I am interested in finding out if there is an improved method for executing this computation:

df = a DataFrame with 500 rows and 20 columns

for index, row in df.iterrows():
    df.loc[index, 'words'], df.loc[index, 'count'] = transcribe(df.loc[index, 'text'])
    df.to_csv('out.csv', encoding='utf-8', index=False)

Currently, the script outputs the full df dataframe as *.csv every time (for each row), including the added values for the computed rows "words" and "counts" up to that point. I would like to know if it is possible to only output complete lines in the csv file, rather than the entire dataframe.

Thank you!

Answer №1

It puzzles me why you prefer to process the dataframe row by row instead of writing it out in one go, but here's a solution tailored to your request: save slices of the dataframe (i.e. the current row) using append mode, including the header only for the initial row:

is_first_row = True
for index, row in df.iterrows():
    df.loc[index, 'words'], df.loc[index, 'count'] = transcribe(df.loc[index, 'text'])
    df.loc[index:index].to_csv('out.csv', encoding='utf-8', index=False, mode='a', header=is_first_row)
    is_first_row = False


Update based on comment that script could be interrupted:
If interruptions are a concern, you can decide whether to include the header by checking if the file exists or is new:

with open('out.csv', encoding='utf-8', mode='a') as f:
    for index, row in df.iterrows():
        df.loc[index, 'words'], df.loc[index, 'count'] = transcribe(df.loc[index, 'text'])
        df.loc[index:index].to_csv(f, index=False, header=f.tell()==0)

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