I am encountering a frustrating issue with a JSON parse error. I can't seem to determine whether the web service is faulty or if there's an issue with my fetch code. When testing the web service on Postman, it returns two objects. However, whenever I try to login using this web service, it consistently gives me a parse error. https://i.stack.imgur.com/YxABw.png
https://i.stack.imgur.com/am7qJ.png
Within my React Native function to loginUser, there may be an error present:
UserLoginFunction = () =>{
const { UserContact } = this.state ;
const { UserPassword } = this.state ;
if(this.state.UserContact == ""){
ToastAndroid.show('Please Enter Contact Number Correctly',ToastAndroid.SHORT)
}
else if (this.state.UserPassword == ""){
ToastAndroid.show('Please Enter Password Correctly',ToastAndroid.SHORT)
}
else{
fetch(urls.localhosturl + urls.login, {
method: 'POST',
headers: {
'Accept': 'application/json',
'Content-Type': 'application/json',
},
body: JSON.stringify({
user_contact: UserContact,
user_password: UserPassword,
//user_name: UserName,
})
})
.then((response) => response.json())
.then((responseJson) => {
console.log(responseJson)
if(responseJson === 'Data Matched')
{
AsyncStorage.setItem("userContact", JSON.stringify(UserContact));
this.props.navigation.navigate('Home',{user_contact:UserContact,});
}
else{
ToastAndroid.show(responseJson,ToastAndroid.SHORT);
}
}).catch((error) => {
console.error(error);
});
}
}The PHP webservice code snippet is as follows:
<?php
include 'config.php';
$con = mysqli_connect($host_name, $host_user, $host_password, $database_name);
$json = file_get_contents('php://input');
$obj = json_decode($json, true);
$user_contact = $obj['user_contact'];
$user_password = $obj['user_password'];
$Sql_Query = "select * from user_information where user_contact = '$user_contact' and user_password = '$user_password' ";
$check = mysqli_fetch_array(mysqli_query($con, $Sql_Query));
if (isset($check)) {
$SuccessLoginMsg = 'Data Matched';
$SuccessLoginJson = json_encode($SuccessLoginMsg);
echo $SuccessLoginJson;
} else {
$InvalidMSG = 'Invalid Username or Password Please Try Again';
$InvalidMSGJSon = json_encode($InvalidMSG);
echo $InvalidMSGJSon;
}
$result = $con->query($Sql_Query);
$array = $result->fetch_assoc();
$json = json_encode($array, true);
echo $json;
mysqli_close($con);