Currently, I am in the process of structuring an AngularJS (Angular 1) project using TypeScript. To compile TypeScript & ES6 to JavaScript, I have set up webpack.
In my webpack configuration, I only compile the "app.ts" file and any other files it imports using the "import" syntax:
import { config } from './config';///<--HERE
module angularSeed {
'use strict';
// Declare app level module which depends on views, and components
angular.module('myApp', [
'ngRoute',
'myApp.view1',
'myApp.view2',
'myApp.version'
]).config(config)//<-- using imported config.ts
}
I aim to divide my project into Angular submodules and include them in the main module like so:
angular.module('mainApp',['myApp.version','myApp.view1','myApp.view2'])
My question is: How can I export these submodules?
One method I've discovered so far is defining the module-definition files as classes:
class view1 {
constructor(){
angular.module('myApp.view1', ['ngRoute'])
.config(['$routeProvider', ($routeProvider: angular.route.IRouteProvider) => {
$routeProvider.when('/view1', {
templateUrl: 'view1/view1.html',
controller: 'View1Ctrl'
});
}])
.controller('View1Ctrl', [() => {
}]);
}
}
export default view1;
Then, in the main file, using "new" to call the constructor:
import { config } from './config';
import view2 from './view2/view2';
import view1 from './view1/view1';
import version from './components/version/version';
module angularSeed {
'use strict';
new view2();///<-- HERE
new view1();
new version();
// Declare app level module which depends on views, and components
angular.module('myApp', [
'ngRoute',
'myApp.view1',
'myApp.view2',
'myApp.version'
]).config(config)
}
I wonder if there is a more precise way to do this. Any insights would be greatly appreciated.
Thank you.