Pairing static letters with changing numbers

How can I use preg_match to find fixed letters with a variable number?

For example:

#^[1-9][0-9]*$#

This code aims to match two numbers at the beginning of any string, such as 1 and 0.

I want to match strings in a file that follow a pattern like r00, r01, r02, r03... up to r999

I attempted the following:

#r^[1-9][0-9]*$#

*This is using Preg_Match function

However, this approach did not work. Any suggestions or assistance would be appreciated?

Answer №1

Utilize this specific pattern:

#^r\d{2,3}$#

For more information, check out the detailed explanation.

Answer №2

^ symbolizes the "beginning of a line", but within brackets, it signifies "everything except the specified characters".

For your requirement, consider using #r\d{2,3}#, possibly with a preceding ^, or following $ (excluding the hashes).

Answer №3

Consider using this pattern if you need to stop at r999:

#^r[0-9]{2,3}$#

This specific pattern will identify:

  • The beginning of the sequence (^)
  • The letter r
  • Between two and three digits ranging from 0 to 9
  • The end of the string ($)

You could also opt for this alternative pattern if there is no fixed upper limit— allowing r999999 as valid:

#^r[0-9]{2,}$#

What this second pattern will match:

  • The start of the sequence (^)
  • The letter r
  • Two or more digits from 0 to 9
  • The end of the string ($)

Answer №4

Here's what I think:

\br\d{1,3}\b

This regular expression will find patterns like r0, r00, r01, r02, r03... up to r999 but it won't match anything like r\d{4,}

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