Populate a pair of div elements using just one AJAX request

Currently, I am attempting to use the load() function to ajaxly load two separate divs, #follow-x and #follow-y, by clicking a button. The approach I have taken is as follows within the success function of my code snippet. However, this method does not seem to be working properly. When I remove one of the functions, it successfully loads only one div, but ideally I would like both divs to be loaded simultaneously. Any assistance on this matter would be greatly appreciated.

$('#follow').click(function(){

          $.ajax({

                   type: "POST",
                   url: "{% url 'follow_class' %}",
                   data: {'pk': '{{class.pk}}' , 'csrfmiddlewaretoken': '{{ csrf_token }}'},
                   dataType: "json",
                   success: function(){
                       $('#follow-x').load("{% url 'class_details' %} #follow-x");
                       $('#follow-y').load("{% url 'class_details' %} #follow-y");}

              }); 
        });
</script>

Please disregard the tags {}, as they are specific to the Django framework that I am using.

Answer №1

only the initial function gets invoked upon success

combine both actions into a single function

$('#follow').click(function(){

          $.ajax({

                   type: "POST",
                   url: "{% url 'follow_class' %}",
                   data: {'pk': '{{class.pk}}' , 'csrfmiddlewaretoken': '{{ csrf_token }}'},
                   dataType: "json",
                   success: function(){
                       $('#follow-x').load("{% url 'class_details' %} #follow-x");                        
                       $('#follow-y').load("{% url 'class_details' %} #follow-y");
                    }

              }); 
        });

Answer №2

The second load function is within another function that remains unused

$('#follow').click(function(){

          $.ajax({

                   type: "POST",
                   url: "{% url 'follow_class' %}",
                   data: {'pk': '{{class.pk}}' , 'csrfmiddlewaretoken': '{{ csrf_token }}'},
                   dataType: "json",
                   success: function(){
                       $('#follow-x').load("{% url 'class_details' %} #follow-x");
                       $('#follow-y').load("{% url 'class_details' %} #follow-y");
                   }

              }); 
        });
</script>

Answer №3

Achievement is a characteristic of the data sent to AJAX. In your script, there is an attempt to assign it within a function that includes the follow-x code, but an error in syntax occurs because the subsequent function statement violates the structure of the object. Consider trying this approach.

success: function(){
     $('#follow-x').load("{% url 'class_details' %} #follow-x");
     $('#follow-y').load("{% url 'class_details' %} #follow-y");
}

It may be helpful to utilize the done callback rather than success. For more information on this, you can visit this link explaining the difference between success and .done() methods of $.ajax

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