Python code example: How to compare two dictionaries stored in a list

Question

Python code example: How to compare two dictionaries stored in a list

I am struggling with creating a script to compare two dictionaries that are stored in a list without knowing the names of the dictionaries. Can someone assist me with this?

Sample code: Is my approach correct? If not, please guide me towards the right solution. Here, "dct_list_cluster" is a list containing two dictionaries.

Code:

for count in range(len(dct_list_cluster)):
  if dct_list_cluster[count].keys() in dct_list_cluster[count+1].keys():
     fo = open("cluster_" + str(ip_list[count]) + "_output.txt", "a")
     fo.write("\n=> %s" % (dct_list_cluster[key])

python dictionary

Answer 1

Answer №1

If my understanding is correct

You have the option to utilize list comprehension

code:

lst=[{"a":2,"b":3,"c":4},{"b":4}]
[a for a in lst[0] if a in lst[1]]
['b']

A way to do it without using list comprehension

code:

lst=[{"a":2,"b":3,"c":4},{"b":4}]
for a in lst[0]:
    if a in lst[1]]:
        print a

output:

Process:

1. When iterating through the dictionary, you are looping through the keys of the dictionary

there are methods to loop through values and both keys and values

2. Checking if it exists in the second dictionary and then printing it

edit:

lst=[{"a":2,"b":3,"c":4},{"b":4},{"b":2,"d":6},{"d":4}]


for count in range(len(lst)-1):
   for a in lst[count]:
      if a in lst[count+1]:
         print "dic"+str(count)+"\t"+str(a)+"\tis common to next dic"

output:

dic0    b       is common to next dic
dic1    b       is common to next dic
dic2    d       is common to next dic

Answer 2

If my understanding is correct

You have the option to utilize list comprehension

code:

lst=[{"a":2,"b":3,"c":4},{"b":4}]
[a for a in lst[0] if a in lst[1]]
['b']

A way to do it without using list comprehension

code:

lst=[{"a":2,"b":3,"c":4},{"b":4}]
for a in lst[0]:
    if a in lst[1]]:
        print a

output:

Process:

1. When iterating through the dictionary, you are looping through the keys of the dictionary

there are methods to loop through values and both keys and values

2. Checking if it exists in the second dictionary and then printing it

edit:

lst=[{"a":2,"b":3,"c":4},{"b":4},{"b":2,"d":6},{"d":4}]


for count in range(len(lst)-1):
   for a in lst[count]:
      if a in lst[count+1]:
         print "dic"+str(count)+"\t"+str(a)+"\tis common to next dic"

output:

dic0    b       is common to next dic
dic1    b       is common to next dic
dic2    d       is common to next dic

Python code example: How to compare two dictionaries stored in a list

Answer №1

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