I'm exploring ways to encode 4 integers into a single byte.
In the code snippet below, I manage to unpack \x11 and extract the bits (resulting in: 1 2 0 0). But how can I reverse this process? In other words, how do I pack 1 2 0 0 back into \x11?
import struct
val = struct.unpack('B', '\x11')[0]
a = val & 7
b = (val >> 3) & 7
c = (val >> 6) & 1
d = (val >> 7)
print a, b, c, d
This is all fairly new to me... any help is greatly appreciated!
Here's an example:
result = ((x & 1) << 7) | ((y & 1) << 6) | ((z & 7) << 3) | (w & 7)
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