Simplify typing in TypeScript using default generic parameters

Imagine I came across the following object:

const inquiries = {
    whoCreatesIssues: {
        options: {
            sameTeam: {
                id: 'SAME_TEAM'
            },
            management: {
                id: 'MANAGEMENT'
            }
        }
    },
    issuesUseCase: {
        options: {
            engineering: {
                id: 'ENGINEERING'
            },
            product: {
                id: 'PRODUCT'
            }
        }
    }
}

I am interested in defining a type SurveyQuestionOptionsKeys so that, for instance,

SurveyQuestionOptionsKeys<'issuesUseCase'> == 'engineering' | 'product'

Currently, I have two types to achieve this. Is there a way to simplify it into just one type? Thank you!

Answer №1

To simplify things, start by isolating the Questions and creating a new type for it:

type Questions = typeof questions;
type SurveyQuestionsOptionsKeys<K extends keyof Questions> = keyof Questions[K]['options'];
type X = SurveyQuestionsOptionsKeys<'issuesUseCase'>;

(Alternatively, you can replace both instances of Questions with typeof questions, but this may make the code less clear to grasp on first glance)

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