Speedy Typescript inquiry query

Question

Speedy Typescript inquiry query

I'm currently in the process of creating a basic endpoint by following the Fastify with Typescript documentation linked below:

https://www.fastify.io/docs/v3.1.x/TypeScript/

export default async function customEndpoint(fastify: any) {
       const MyInstance = new CustomClass(fastify.db);
       app.get<{ Querystring: IQueryString, Headers: IHeaders }>(
           "/custom",
           async (request: FastifyRequest, reply: FastifyReply) => {
              console.log(request.query); // *output query object*
              const { queryObj } = request.query; // *Throws error: Object is of type 'unknown'*
              const result = await MyInstance.getCustom(queryObj);
              reply.status(200).send(result);
           }
       );
   }

Can someone explain why an error occurs when trying to access the request.query object and provide suggestions on how to resolve it?

node.js typescript fastify

Answer 1

Answer №1

In the standard configuration, FastifyRequest.query is mapped to unknown as RequestQuerystringDefault since it's impossible to predict what attributes or type you will assign to it.

If you have a specific type for the query in a request, simply define that particular request type and use it:

type MyRequest = FastifyRequest<{
  Querystring: { queryObj: MyQueryObject }
}>

Then indicate it as the expected request type:

 async (request: MyRequest, reply: FastifyReply) => {
   const { queryObj } = request.query // Ok
 }

Answer 2

In the standard configuration, FastifyRequest.query is mapped to unknown as RequestQuerystringDefault since it's impossible to predict what attributes or type you will assign to it.

If you have a specific type for the query in a request, simply define that particular request type and use it:

type MyRequest = FastifyRequest<{
  Querystring: { queryObj: MyQueryObject }
}>

Then indicate it as the expected request type:

 async (request: MyRequest, reply: FastifyReply) => {
   const { queryObj } = request.query // Ok
 }

Speedy Typescript inquiry query

Answer №1

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