Strip out any HTML code from scraped content that does not contain an identifier or class

I am seeking a way to eliminate specific html code from the data I am scraping, however, I am unable to isolate it by its id or class. It is necessary to erase every occurrence of this particular code within the html.

<ul data-bfa="@l:Subbuzz-Share;">
    <!-- MORE CODES -- >
</ul>

Answer №1

If you want to remove a specific element from an HTML tag, you can use either str_replace or regex (regular expression) methods

For this example, let's start with using str_replace:

// Define a variable containing the html tag
$html = '
   <ul data-bfa="@l:Subbuzz-Share;">
    <!-- MORE CODES -- >
  </ul>
';

// Remove the specified element using str_replace
$html = str_replace('data-bfa="@l:Subbuzz-Share;"','',$html);

For more information on str_replace, visit: https://www.php.net/manual/tr/function.str-replace.php

Now, let's explore using regex, which is versatile for various cases:

// Define a variable containing the html tag
$html = '
   <ul data-bfa="@l:Subbuzz-Share;">
    <!-- MORE CODES -- >
  </ul>
';

// Remove the element using preg_replace and regex
$html = preg_replace('data-bfa=".+"','',$html);

// Another way to remove the element using regex
$html = preg_replace('data-.+=".+"','',$html);

For more information on preg_replace with regex, visit: https://www.php.net/manual/tr/function.preg-replace.php

Additionally, you can practice and test your regex patterns on this useful site:

Edit: To be more specific in removing the html tag type:

// Using str_replace may not be ideal for this scenario
$html = str_replace('<ul data-bfa="@l:Subbuzz-Share;">','<ul>',$html);

// Using preg_replace to remove the specified element
$html = preg_replace('(<ul )data-.+=".+"','$1',$html);

// Another way of using preg_replace to remove the element
$html = preg_replace('(<ul .+) data-.+=".+"','$1',$html);

If you find regex confusing, take some time to study and understand how it works :)

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