Struggling to achieve proper alignment for a series of div tags

I have implemented a code block to read in an image pixel by pixel and display it as a series of div tags arranged in a table-like fashion. The code is mostly inspired by a comment on PHP.net (http://www.php.net/manual/en/function.imagecolorat.php). This is my implementation:

<?php 
$img = imagecreatefrompng("image1.png"); 

$width = imagesx($img); 
$height = imagesy($img); 

for($y=0;$y<$height;$y++) { 
   for($x=0;$x<$width;$x++) { 
      $rgb = imagecolorat($img, $x, $y); 
      $r = ($rgb >> 16) & 0xFF; 
      $g = ($rgb >> 8) & 0xFF; 
      $b = $rgb & 0xFF;
      $hex = "#".str_repeat("0",2-strlen(dechex($r))).dechex($r). 
              str_repeat("0",2-strlen(dechex($g))).dechex($g). 
              str_repeat("0",2-strlen(dechex($b))).dechex($b);
     echo "<div style='background: {$hex}; height: 5px; width: 5px; display: inline;'></div>\r\n";
     /*
        echo "#".str_repeat("0",2-strlen(dechex($r))).dechex($r). 
              str_repeat("0",2-strlen(dechex($g))).dechex($g). 
              str_repeat("0",2-strlen(dechex($b))).dechex($b).","; 
     */ 
  } 
  echo "<br />\r\n"; 
} 
?>

I have experimented with different values for the display property such as 'block', 'inline', 'inline-block' and 'inline-table'. However, each option seems to introduce its own issues. I either get no output at all, columns of pixels forming a vertical line, or correctly aligned divs but with unnecessary spacing (which is unexpected since I am using a reset.css file to remove padding and spacing).

Additionally, this code does not handle transparency properly. The image I'm using contains transparent pixels, but they are being displayed as light blue.

You can find my implementation here.

Answer №1

Well, this is quite an intriguing situation. I cannot guarantee that function would consider transparency, but resolving the HTML positioning issue should be a straightforward task.

In my opinion, the optimal solution would involve creating a container with the same width as the image, and then floating all of the divs to the left. It could look something like this:

echo "<div style='width: ".($imagesx * 5)."px;' class='outer'>";

This approach will provide the necessary width (assuming that I correctly understand the code). Afterwards, you simply apply this CSS:

.outer div {
  width: 5px;
  height: 5px;
  float: left;
}

By doing so, you'll effectively reduce the redundancy of inline styles that need to be generated. Moreover, remember to remove the br tag that appears after each row.

If you are facing problems with alpha transparency, I believe this comment might come in handy: http://www.php.net/manual/en/function.imagecolorat.php#79116


Edit

It seems you forgot to include the px unit for width: 65px! This part is being automatically generated.

<div style='width: 65; background: #eeeeee; margin: 0px auto;'>

On a side note, that Mario character is pretty cool. ;)

Answer №2

 echo "<div style='border-color: {$hex}; height: 10px; width: 10px; position: relative; top: {$y * 5}; left: {$x * 7}; background-color: white;'></div>\r\n";

To ensure proper alignment, it is recommended to place them all within a parent element with position: relative;. Additionally, consider removing any unnecessary line breaks.

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