I am attempting to optimize the code by using a ternary operator to quickly return false. My understanding was that using a ternary in this scenario would have the same outcome as the if statement below it, which is to instantly return false if the lengths of the two arrays do not match. However, I am unable to comprehend why the ternary operator does not seem to be affecting the code's execution.
function checkEquality(arrOne, arrTwo) {
// Shouldn't this ternary and if statement achieve the same result?
// arrOne.length !== arrTwo.length ? false : {}
if (arrOne.length !== arrTwo.length) {
console.log(false);
return false;
}
let result = {};
// Add number frequencies to the result object
arrOne.forEach((num) => {
result[num] ? result[num]++ : (result[num] = 1);
});
// Check if square matches root within the object
arrTwo.forEach((num) => {});
console.log(result);
}
checkEquality([1, 2, 3, 4], [4, 1, 9]); // False - Lengths do not match
// checkEquality([1,2,3], [1,9]) // False
// checkEquality([1,2,1], [4,4,1]) // False - Frequencies must be the same
`
In an effort to improve performance, I tried utilizing a ternary operator to immediately return false if the lengths of the input arrays are not equal. Unfortunately, it seems that the ternary operator has no effect on the code's behavior.