Recently, I embarked on the journey of programming and encountered a code that involved finding the smallest value among 10 integer inputs. Here is my code:
x, y = 0, 0
while x < 10:
n = int(input())
y += n
x += 1
print(y)
s = min(y)
print(s)
Despite my efforts, an issue arose when trying to execute 's = min(y)' which resulted in a TypeError: 'int' object is not iterable. How can I rectify this problem?
When you add one int to another, the result is a single int, not a pair of two separate integers. If you try to use the min function on just an int, it will throw an error because it expects an iterable such as a list.
Here is the corrected way to achieve this:
x, y = 0, []
while x < 10:
n = int(input())
y.append(n)
x += 1
print(y)
Now that y is a list of integers, you can find the smallest value in it using the min function like this:
s = min(y)
print(s)
An alternative method to create y more efficiently is by using a list comprehension along with a range:
y = [int(input()) for _ in range(10)]
print(min(y))
Don't expect Python to return the minimum number of one number when using the min() function, it doesn't work that way.
Instead, you can find the minimum of a list of numbers by using min([5,2]) -> 2. So make sure to write:
x = min([z])
This will assign the value of z to x.
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