Tips for arranging a secondary list according to the order of the first list?

Struggling to sort an ordered list based on the order of an unordered list? I attempted to do so by manipulating the indexes of each element in both lists without success. If anyone has faced a similar challenge or knows the right function to use, I'd appreciate the guidance.

unordered_list = ['North_America', 'Europe', 'Asia', 'Antarctica',  'Australia', 'Africa']

ordered_list =   ['Africa.jpg', 'Asia.jpg', 'Antarctica.jpg', 'Australia.jpg', 'Europe.jpg', 'North_America.jpg']

# The desired reordering for this case: [5,4,1,2,3,1]

The desired output:

ordered_list = ['North_America.jpg', 'Europe.jpg', 'Asia.jpg', 'Antarctica.jpg',  'Australia.jpg', 'Africa.jpg']
pythonsortingindexing

Answer №1

Below is the resulting output:

['North_America.jpg', 'Europe.jpg', 'Asia.jpg', 'Antarctica.jpg',  'Australia.jpg', 'Africa.jpg']

This snippet represents the code used to generate the list above:

unordered_list = ['North_America', 'Europe', 'Asia', 'Antarctica',  'Australia', 'Africa']
ordered_list =   ['Africa.jpg', 'Asia.jpg', 'Antarctica.jpg', 'Australia.jpg', 'Europe.jpg', 'North_America.jpg']

corrected_list = []

for x in unordered_list:
    for y in range(len(ordered_list)):
        if x in ordered_list[y]:
            corrected_list.append(ordered_list[y])
            break
            
print(corrected_list)

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