export const isFunction = (obj: unknown): obj is Function => obj instanceof Function;
export const isString = (obj: unknown): obj is string => Object.prototype.toString.call(obj) === "[object String]";
I need to create an isFunction method, similar to the isString method. However, when working with typescript/eslint, I encountered this error message:
Avoid using 'Function' as a type. The 'Function' type allows any function-like value,
which can lead to lack of type safety during function calls and potential bugs.
It also includes things like class declarations, which may cause runtime errors if not called correctly with `new`.
If you expect a function to have specific arguments, it's best to explicitly define its shape @typescript-eslint/ban-types
Is there a way around this issue?
P.S. Solution provided below:
export const isFunction = (obj: unknown): obj is (...args: any[]) => any => obj instanceof Function;