I am attempting to store the on or off value from a form into an SQL database by calling a JS function with an AJAX request that sends it to a PHP page for processing. I seem to be facing some issues with my code and could really use some assistance as the API documentation hasn't been very clear. Any help would be greatly appreciated!
Below is the current code snippet:
<?php require('../php/validation.php');?>
<?php require('../php/background.php');?>
<?php
if(isset($_POST['selectonoff'])){
$_SESSION['onoff'] = $_POST['selectonoff'];
$query = 'UPDATE onoff SET onoroff = $_POST["selectonoff"] WHERE ID = 1;';
$update = mysqli_query($db, $query);
}
?>
<!DOCTYPE html>
<html lang="en" >
<head>
<meta charset="UTF-8">
<title>User Settings Dropdown Menu</title>
<link rel="stylesheet" href="../css/settings.css">
<script type="text/javascript">
function load() {
document.getElementById("selectonoff").value = '<?php echo $_SESSION['onoff'];?>';
}
</script>
<script src="jquery.js"></script>
<script>
function rel(id)
{
jQuery.ajax({
type: "POST",
data: 'id='+id,
url: "../php/update.php",
cache: false,
success: function(response)
{
alert("Record successfully updated");
}
});
}
</script>
</head>
<body onload="load();">
<!-- <div id="wrap"> -->
<br><br><br><br>
<h1>Admin Settings Menu</h1>
<form method="post" action="adminconfig.php">
<p>Toggle BBQ Form</p>
<select id="selectonoff" name="selectonoff" onchange="this.form.submit(); rel();">
<option value="NONE">Select</option>
<option value="ON">Toggle ON</option>
<option value="OFF">Toggle OFF</option>
</select>
</form>
<form action="../index.php">
<input type="submit" value="Home" />
</form>
<script type="text/javascript"=>
</script>
</body>
<script src='http://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.min.js'></script>
<script src="../js/index.js"></script>
</html>
Current PHP Code:
<?php
require ('php/server.php');
$database = mysqli_connect('localhost', 'root', '', 'dedricks');
if(!$database){
die("Connection Failed: ".mysqli_connect_error());
}
$data = @$_POST['id'] ;
$sqlQuery = 'UPDATE onoff SET onoroff = $data WHERE ID = 1;';
mysqli_query($database, $sqlQuery);
?>