Having trouble navigating to the next post on my Instagram bot. Here are my attempts:
#First Attempt
next_button = driver.find_element_by_class_name('wpO6b ')
next_button.click()
#Second Attempt
_next = driver.find_element_by_class_name('coreSpriteRightPaginationArrow').click()
Unfortunately, both attempts resulted in a NoSuchElementException or ElementClickInterceptedException. What changes should I make?
This is the button I'm trying to click (to move to the next post):
Upon inspecting your code, I found that the class name coreSpriteRightPaginationArrow was not present in any element. However, I did notice a partial match of the class name. To address this issue, you can utilize the following XPath with the 'contains' function:
//div[contains(@class,'coreSpriteRight')]
Additionally, there is another xpath using the class wpO6b, which has 10 elements sharing the same class name. You can filter these elements by using @aria-label='Next':
//button[@class='wpO6b ']//*[@aria-label='Next']
Please try implementing these XPaths and let me know if they resolve your query.
I have tested the provided code snippet and confirmed that it successfully clicks the next button 10 times:
import time
from selenium import webdriver
from selenium.webdriver.common.by import By
if __name__ == '__main__':
driver = webdriver.Chrome('/Users/yosuvaarulanthu/node_modules/chromedriver/lib/chromedriver/chromedriver')
driver.maximize_window()
driver.implicitly_wait(15)
driver.get("https://www.instagram.com/instagram/");
time.sleep(2)
driver.find_element(By.XPATH,"//button[text()='Accept All']").click();
time.sleep(2)
driver.find_element(By.NAME,"username").send_keys('username')
driver.find_element(By.NAME,"password").send_keys('password')
driver.find_element(By.XPATH,"//div[text()='Log In']").click();
driver.find_element(By.XPATH,"//button[text()='Not now']").click();
driver.find_element(By.XPATH,"//button[text()='Not Now']").click();
driver.get("https://www.instagram.com/instagram/");
driver.find_element(By.XPATH,"//div[@class='v1Nh3 kIKUG _bz0w']").click();
for page in range(1,10):
driver.find_element(By.XPATH,"//button[@class='wpO6b ']//*[@aria-label='Next']" ).click();
time.sleep(2)
driver.quit()
Looking at the image provided below, you can observe that the wp06b button is nested within several layers of divs. In this scenario, you may need to specify the same path of divs to Selenium in order to access the button, or provide it with an appropriate XPath.
https://i.stack.imgur.com/N4Ard.png
This method might not be the most efficient, but it should function correctly.
driver.find_element(By.XPATH("(.//*[normalize-space(text()) and normalize-space(.)='© 2022 Instagram from Meta'])[1]/following::*[name()='svg'][2]")).click()
Please note that the XPath points to an svg element, meaning we are actually clicking on the svg itself rather than the button.
Notice how the right arrow button element locator changes from the first post to subsequent posts on the next page.
For the first post, use this locator:
//div[contains(@class,'coreSpriteRight')]
For all other posts, use this locator instead:
//a[contains(@class,'coreSpriteRight')]
The second element
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