Utilizing decorator functions to yield the return of a wrapper

I have a question regarding the process of returning the wrapper in this code snippet. Why is it necessary to return the wrapper and where exactly is it being returned to? I understand that when I return the wrapper, it returns a pointer, but I'm confused about the purpose and location of this return action. Shouldn't I simply call it within the deco function like this: def deco(fun): ......... wrapper().

import  time

def deco(fun) :
    def wrapper(*args) :
        start_time = time.time()

        result = fun(*args)

        end_time = time.time()

        print(f"{end_time - start_time} seconds elapsed")

        return result
    return wrapper


@deco
def average (list):
    total = 0
    for number in list:
        total += number
    return total

numbers_list = list(range(0,10))
result = average(numbers_list)
print(result)

Answer №1

deco is a higher-order function that takes another function as an argument and returns a new function.

By using deco, the original ortalama function gets replaced with the modified function deco(ortalama).

Answer №2

Decorator functions are a powerful tool that can wrap around target functions and modify their input and output values. By returning an inner wrapper function, the decorator function seamlessly replaces the original target function.

When using a decorator annotation, the original function is substituted with a wrapper function.

> print(average)

<function deco.<locals>.wrapper at 0x7f7d6beea048>

Without applying a decorator, the function remains as originally defined

> print(average)

<function average at 0x7f7d6beea158>

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