Verify the Element and proceed to the subsequent tag

I have a list with various elements, each containing its own delete button. If I want to delete a specific element (such as Test 1 or Test 2), I first need to confirm the element and then proceed with deleting it.

<div class="html-replace-container">
<form id="new_supplier_assignment" class="new_supplier_assignment" action="/supplier_assignments" accept-charset="UTF-8" method="post">
<h3 class="supplier-assignment-header progress-active">
<a href="/products/685">Test 1</a>

  -
<a href="/companies/13">Test 2</a>
</h3>
<a class="btn btn-danger btn-sm" data-replace-html-container="true" data-confirm="Are you sure?" style="float: right" rel="nofollow" data-method="delete" href="/supplier_assignments/122?owner=Customer">Delete</a>

So far, I have this:

<tr>
    <td>click</td>
    <td>xpath=//*[@id='new_supplier_assignment']/..//*[contains(text(), 'Test 1')]/../*[contains(text(), 'Test 2')]</td>
    <td></td>
</tr>

I need to locate the 

<a class="btn btn-danger ...>
and click on it without using count() or indexof().

seleniumselenium-ide

Answer №1

To begin, locate an h3 element where the first a tag contains the text "Test 1" and the second a tag contains the text "Test 2". Then, use the following-sibling::a axis to find the delete button.

XPath: 

//h3[a[1][text()="Test 1"] and a[2][text()="Test 2"]]/following-sibling::a

If you are not concerned with which a tag is "Test 1" (it could be the first or second), you can omit the indexes [1] and [2]. Try the following XPath:

//h3[a[text()="Test 1"] and a[text()="Test 2"]]/following-sibling::a

Answer №2

If you want to locate an element using text, you can use the following code:

driver.findElement(by.xpath("//a[contains(text(), 'YOUR TEXT')]")).click()

The buttons are identified by their different texts - 'Test 1' and 'Test 2', so you can easily locate and manipulate them based on their text content.

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