Ways to verify if certain text information is present on the webpage

Question

Ways to verify if certain text information is present on the webpage

Is there a specific way to determine if certain texts are present on a webpage? It would be ideal to check multiple texts at once.

For instance, checking for "client", "customer", and "order" in the page content.

Below is an example of the HTML code snippet:

<div class="findText"><span>Example text. Football.</span></div>

Once verification is completed, I plan to use an "if" condition like this one. However, my current method may not be the most efficient, as it only allows for single-word checks using logical OR (||) operators.

 if(driver.getPageSource().contains("google"))  {
   driver.close();
   driver.switchTo().window(winHandleBefore);
}

Additionally, is there a way to input a large list of words for validation purposes all at once?

java selenium selenium-webdriver automation

Answer 1

Answer №1

if(checkIfStringContainsWord(driver.getPageSource(), new String[] {"google", "otherword"))
{
    driver.close();
    driver.switchTo().window(winHandleBefore);
}

 public static boolean checkIfStringContainsWord(String inputStr, String[] words)
    {
        for(int i =0; i < words.length; i++)
        {
            if(inputStr.contains(words[i]))
            {
                return true;
            }
        }
        return false;
    }

checkIfStringContainsWord() method from Test if a string contains any of the strings from an array

If you prefer to extract just the text of that element, consider using this alternative approach instead of calling driver.getPageSource()...

driver.findElement(By.cssSelector("div.findText > span")).getText();

Answer 2

if(checkIfStringContainsWord(driver.getPageSource(), new String[] {"google", "otherword"))
{
    driver.close();
    driver.switchTo().window(winHandleBefore);
}

 public static boolean checkIfStringContainsWord(String inputStr, String[] words)
    {
        for(int i =0; i < words.length; i++)
        {
            if(inputStr.contains(words[i]))
            {
                return true;
            }
        }
        return false;
    }

checkIfStringContainsWord() method from Test if a string contains any of the strings from an array

If you prefer to extract just the text of that element, consider using this alternative approach instead of calling driver.getPageSource()...

driver.findElement(By.cssSelector("div.findText > span")).getText();

Answer 3

Answer №2

Check out the Java 8 Streaming API

import java.util.Arrays;

public class Test {

    private static final String[] positiveWords = {"love", "kiss", "happy"};

    public static boolean containsPositiveWords(String enteredText, String[] positiveWords) {
        return Arrays.stream(positiveWords).parallel().anyMatch(enteredText::contains);
    }

    public static void main(String[] args) {
        String enteredText1 = " Yo I love the world!";
        String enteredText2 = "I like to code.";
        System.out.println(containsPositiveWords(enteredText1, positiveWords));
        System.out.println(containsPositiveWords(enteredText2, positiveWords));
    }
}

Output:

true
false

You could also utilize ArrayList with .parallelStream() instead.

Answer 4

Check out the Java 8 Streaming API

import java.util.Arrays;

public class Test {

    private static final String[] positiveWords = {"love", "kiss", "happy"};

    public static boolean containsPositiveWords(String enteredText, String[] positiveWords) {
        return Arrays.stream(positiveWords).parallel().anyMatch(enteredText::contains);
    }

    public static void main(String[] args) {
        String enteredText1 = " Yo I love the world!";
        String enteredText2 = "I like to code.";
        System.out.println(containsPositiveWords(enteredText1, positiveWords));
        System.out.println(containsPositiveWords(enteredText2, positiveWords));
    }
}

Output:

true
false

You could also utilize ArrayList with .parallelStream() instead.

Ways to verify if certain text information is present on the webpage

Answer №1

Answer №2

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