What is the appropriate way to notify Gulp when a task has been completed?

I have been working on developing a gulp plugin that counts the number of files in the stream. Taking inspiration from a helpful thread on Stack Overflow (source), I started implementing the following code:

function count() {

  var count = 0;

  function countFiles(data) {
    count++;
    // following official documentation:
    this.queue(data);
  }

  function endStream() {
    console.log(count + " files processed");
    // Instead of ending the chain like the original post, I am using the following as per the docs:
    this.queue(null);
  }

  return through(countFiles, endStream);
}


module.exports = count;

Furthermore, here is an example task utilizing the plugin:

gulp.task("mytask", function () {
  gulp
    .src("...files...")
    .pipe(count());                // <--- incorporating the plugin here
    .pipe(changed("./some/path"))
    .pipe(uglify())
    .pipe(rename({ extname: ".min.js" }))
    .pipe(gulp.dest(./some/path))
    .pipe(count());                // <--- another usage of the plugin
});

The functionality works accurately, albeit not starting or finishing as anticipated:

[14:39:12] Using gulpfile c:\foo\bar\baz\gulpfile.js
[14:39:12] Starting 'mytask'...
[14:39:12] Finished 'mytask' after 9.74 ms
9 files processed
5 files processed

This behavior suggests an asynchronous execution that concludes after the task finishes. The documentation recommends either using a callback or returning a stream, which seems to be implemented here.

How can I rectify this issue with the function's behavior? Could it be caused by my use of through instead of the through2 plugin?

Answer №1

Make sure to add the return statement before gulp in your task. This will indicate to gulp when your stream has finished processing.

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