What is the method for obtaining the union type of interface values (including string enums)?

How can I achieve the following ?

Given :

enum FooEnum1 { 
    Foo = "foo",
};

enum FooEnum2 { 
    Foo = 1,
};

interface FooInterface {
    foo1 : FooEnum1,
    foo2 : FooEnum2,
    foo3 : string,
    foo4 : number,
};

I am interested in creating a union type that includes

FooEnum1 | FooEnum2 | string | number
. This type should encompass all possible values of the interface.

The current attempt with this line of code is not yielding the desired outcome:

type FooInterfaceValuesType = FooInterface[keyof FooInterface]
-> string | number

If I update the interface as follows:

interface FooInterface {
    foo1 : FooEnum1,
    foo2 : FooEnum2
};

The resulting FooInterfaceValuesType becomes FooEnum1 | FooEnum2

Please advise on what may be going wrong. Thank you.

Answer №1

Unfortunately, my reputation is not high enough to leave a comment, but I share the same sentiment as others that it simply doesn't function properly.

For example, if you want to create a union of two specific string values, you can achieve this by defining

type U = "a" | "b"
. However, when you extend this further with
type U = "a" | "b" | string
, the type U essentially collapses down to just string because including "a" and "b" in the union with strings doesn't serve any practical purpose.

Returning to the interface scenario mentioned, foo1 is restricted to being assigned only with FooEnum1.Foo, which is a fixed string value of "foo". Similarly, when combining "foo" with other potential strings or numbers within such unions, they all ultimately boil down to simple strings or numbers due to their inherent nature.

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