When dealing with an array of objects, my goal is to choose the object that has the highest value in one of its fields.
I understand how to select the value itself:
Math.max.apply(Math, list.map(function (o) { return o.DisplayAQI; }))
... but I am unsure of how to achieve the same result and return the entire object instead of just the value.
If you want to find the object in an array with the highest value for the property DisplayAQI, you can achieve this using the reduce method.
let list = [ {DisplayAQI : 20}, {DisplayAQI : 100}, {DisplayAQI : 200}, {DisplayAQI : 10} ];
let result = list.reduce((c, v) => c.DisplayAQI > v.DisplayAQI ? c : v);
console.log(result);Resource: Learn more about reduce() on MDN
myArrayOfObjects.sort((object1, object2) => { return object1.property - object2.property })[0]Just sort your array based on a specific property and fetch the first element from the sorted list.
One alternative method is to organize the array of objects in descending order and then retrieve the element from the 0th index
let values = [{
DisplayAQI: 20
}, {
DisplayAQI: 100
}, {
DisplayAQI: 200
}, {
DisplayAQI: 10
}];
let output = values.sort(function(a, b) {
return b.DisplayAQI - a.DisplayAQI
})[0];
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