"Prior to encoding the MySQL array, it is essential to have an

Question

"Prior to encoding the MySQL array, it is essential to have an

I'm having trouble getting a verification array to load before the mysql array in json_encode. Here is the Array I want displayed before the mysql array: "array("status":"true","message":"Data fetched successfully!","data":" However, when I try running the web service, it just shows up blank. Any suggestions?

<?php

// Establish connection
$con=mysqli_connect("localhost","burtkunt_dbuser","phatelives","burtkunt_colors");

// Check connection status
if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// This SQL query selects ALL data from the 'colors' table
$sql = "SELECT * FROM colors";

// Check if query returns results
if ($result = mysqli_query($con, $sql))
{
    // If there are results, create an empty result array and temporary one
    $resultArray = array();
    $tempArray = array();

    // Iterate through each row in the result set
    while($row = $result->fetch_object())
    {
        // Insert each row into our result array
        $tempArray = $row;
        array_push($resultArray, $tempArray);
    }

    // Finally, encode the array to JSON and display the results
    echo json_encode(array("status":"true","message":"Data fetched successfully!","data":$resultArray));
}

// Close connections
mysqli_close($con);
?>

Here's how I envision the output:

{"status":"true","message":"Data fetched successfully!","data":[{"id":"1","name":"Roger Federer","country":"Switzerland","city":"Basel","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/roger.jpg"},{"id":"2","name":"Rafael Nadal","country":"Spain","city":"Madrid","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/nadal.jpg"},{"id":"3","name":"Novak Djokovic","country":"Serbia","city":"Monaco","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/djoko.jpg"},{"id":"4","name":"Andy Murray","country":"United Kingdom","city":"London","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/murray.jpg"},{"id":"5","name":"Maria Sharapova","country":"Russia","city":"Moscow","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/shara.jpg"},{"id":"6","name":"Caroline Wozniacki","country":"Denmark","city":"Odense","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/woz.jpg"},{"id":"7","name":"Eugenie Bouchard","country":"Canada","city":" Montreal","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/bou.png"},{"id":"8","name":"Ana Ivanovic","country":"Serbia","city":"Belgrade","imgURL":"https:\/\/demonuts.com\/Demonuts\/SampleImages\/iva.jpg"}]}

php mysql arrays json

Answer 1

Answer №1

your list is not in the correct format.

This is the proper format:

$list = array("Peter"=>"35", "Ben"=>"37", "Joe"=>"43");

$json_data = array("status"=>"true", "message"=>"Data retrieved successfully!", "data"=> $resultArray);

echo json_encode($json_data);

Answer 2

your list is not in the correct format.

This is the proper format:

$list = array("Peter"=>"35", "Ben"=>"37", "Joe"=>"43");

$json_data = array("status"=>"true", "message"=>"Data retrieved successfully!", "data"=> $resultArray);

echo json_encode($json_data);

Answer 3

Answer №2

There seems to be a mistake in your PHP array assignment, and I have also noticed some other issues in your code. Here is an updated version:

<?php

// Establish connection
$con=mysqli_connect("localhost","burtkunt_dbuser","phatelives","burtkunt_colors");

// Check if connection was successful
if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// SQL statement to select all from the 'colors' table
$sql = "SELECT * FROM colors";

// Check for results
if ($result = mysqli_query($con, $sql))
{
    // Create an array to store results
    $resultArray = array();

    // Loop through each row in the result set
    while($row = $result->fetch_object())
    {
        // Add each row to the results array
        array_push($resultArray, $row);
    }

    // Convert the array to JSON format and output the data
    echo json_encode(array("status" => "true","message" => "Data fetched successfully!","data" => $resultArray));
}

// Close the connections
mysqli_close($con);
?>

Answer 4

There seems to be a mistake in your PHP array assignment, and I have also noticed some other issues in your code. Here is an updated version:

<?php

// Establish connection
$con=mysqli_connect("localhost","burtkunt_dbuser","phatelives","burtkunt_colors");

// Check if connection was successful
if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// SQL statement to select all from the 'colors' table
$sql = "SELECT * FROM colors";

// Check for results
if ($result = mysqli_query($con, $sql))
{
    // Create an array to store results
    $resultArray = array();

    // Loop through each row in the result set
    while($row = $result->fetch_object())
    {
        // Add each row to the results array
        array_push($resultArray, $row);
    }

    // Convert the array to JSON format and output the data
    echo json_encode(array("status" => "true","message" => "Data fetched successfully!","data" => $resultArray));
}

// Close the connections
mysqli_close($con);
?>

Answer 5

Answer №3

First, you need to select all the values from your database using a loop like this:

This is my method for creating JSON when retrieving data from the database

$tempArray = array();

// Iterate through each row in the result set
while($row = $result->fetch_object())
{

    $data = array("id" => $row['id'], "name" => $row['name'],"country" => $row['country']);
    array_push($temparray, $data);
}
$arr= array("status"=>"true","message"=>"Data fetched successfully!", "data" => $temparray);
echo json_encode($arr);

I hope this helps

Answer 6

First, you need to select all the values from your database using a loop like this:

This is my method for creating JSON when retrieving data from the database

$tempArray = array();

// Iterate through each row in the result set
while($row = $result->fetch_object())
{

    $data = array("id" => $row['id'], "name" => $row['name'],"country" => $row['country']);
    array_push($temparray, $data);
}
$arr= array("status"=>"true","message"=>"Data fetched successfully!", "data" => $temparray);
echo json_encode($arr);

I hope this helps

"Prior to encoding the MySQL array, it is essential to have an

Answer №1

Answer №2

Answer №3

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