The foreach statement in PHP is functioning correctly, however, the message in the else statement is

Question

The foreach statement in PHP is functioning correctly, however, the message in the else statement is

I have been working on fetching data from my model as an array and using a php foreach loop to display it in a specific view. I am now trying to implement an additional layer of logic to only display certain bookmark_ids.

Even though the data is being displayed correctly, I am facing an issue where the "else" message (associated with the initial if statement) does not appear when no data is returned. I need to find a way to ensure that this message is shown.

<?php 

     if ($bookmark): 
     foreach($bookmark as $b): ?>               

     <?php if ($b->bookmark_id != 0) { ?>               

     <li><?php echo $bk->user_id; ?> <?php echo $bk->bookmark_name; ?></li>

     <?php } ?>


     <?php
      endforeach;
        else:
          print "Your bookmark list is empty.";
    endif;

?>

php if-statement foreach

Answer 1

Answer №1

To test the existence of $bookmark, assume it is always present, with either empty or array values.

Give this a try:

<?php 

if (is_array($bookmark) && count($bookmark)>=1): 
  foreach($bookmark as $b):               

    if ($b->bookmark_id != 0) {              

      <li><?php echo $bk->bookmark_name; ?></li>

    }

  endforeach;
else:
  print "Your bookmark list is currently empty.";
endif;

?>

Refer to: PHP is_array() | count()

REVISITED

In response to the recent comment "Yes, the array has results; I am using the second if statement for display restriction. It appears that my else statement should be linked to the second if condition, rather than the first one. My concern is not about having results but filtering them and checking what remains.":

<?php 

// reset the counter
$count = 0;

// for an array that is not empty
if (is_array($bookmark) && count($bookmark)>=1): 
  foreach($bookmark as $b):
    if ($b->bookmark_id != 0) {               
      echo '<li>' . $bk->bookmark_name . '</li>';
    } else {
      $count++; // increase if no data
    }

    // check if the counter was incremented 
    if ($count>=1) {
      print "Your bookmark list is empty.";
    }
  endforeach;
else:
  print "No bookmarks found.";
endif;

?>

Answer 2

To test the existence of $bookmark, assume it is always present, with either empty or array values.

Give this a try:

<?php 

if (is_array($bookmark) && count($bookmark)>=1): 
  foreach($bookmark as $b):               

    if ($b->bookmark_id != 0) {              

      <li><?php echo $bk->bookmark_name; ?></li>

    }

  endforeach;
else:
  print "Your bookmark list is currently empty.";
endif;

?>

Refer to: PHP is_array() | count()

REVISITED

In response to the recent comment "Yes, the array has results; I am using the second if statement for display restriction. It appears that my else statement should be linked to the second if condition, rather than the first one. My concern is not about having results but filtering them and checking what remains.":

<?php 

// reset the counter
$count = 0;

// for an array that is not empty
if (is_array($bookmark) && count($bookmark)>=1): 
  foreach($bookmark as $b):
    if ($b->bookmark_id != 0) {               
      echo '<li>' . $bk->bookmark_name . '</li>';
    } else {
      $count++; // increase if no data
    }

    // check if the counter was incremented 
    if ($count>=1) {
      print "Your bookmark list is empty.";
    }
  endforeach;
else:
  print "No bookmarks found.";
endif;

?>

Answer 3

Answer №2

It seems that $bookmark is returning true for some reason. Given that empty strings and arrays evaluate to false in PHP, it's likely that $bookmark is actually an object. Based on its ability to be iterated over with foreach, it may be an instance of a class like ArrayObject. To determine the exact type of $bookmark, you could use:

var_dump($bookmark);

Since an empty object evaluates to true in a PHP conditional, it's important to be more specific about what condition you're checking for.

if(count($bookmark) > 0):

This should appropriately trigger the else condition. Additionally, remember to properly indent your code for better readability. :)

Answer 4

It seems that $bookmark is returning true for some reason. Given that empty strings and arrays evaluate to false in PHP, it's likely that $bookmark is actually an object. Based on its ability to be iterated over with foreach, it may be an instance of a class like ArrayObject. To determine the exact type of $bookmark, you could use:

var_dump($bookmark);

Since an empty object evaluates to true in a PHP conditional, it's important to be more specific about what condition you're checking for.

if(count($bookmark) > 0):

This should appropriately trigger the else condition. Additionally, remember to properly indent your code for better readability. :)

Answer 5

Answer №3

if (is_array($saved) && !empty($saved)) { 
  foreach ($saved as $link) {               
   ...
  }
} else {
  echo "There are no saved bookmarks.";
}

Answer 6

if (is_array($saved) && !empty($saved)) { 
  foreach ($saved as $link) {               
   ...
  }
} else {
  echo "There are no saved bookmarks.";
}

The foreach statement in PHP is functioning correctly, however, the message in the else statement is

Answer №1

REVISITED

Answer №2

Answer №3

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