Experiencing issues with the functionality of jQuery AJAX?

I am experiencing difficulties with a jQuery AJAX post. Here is the code:

<script>
var callback = function(data) {
    if (data['order_id']) {
        $.ajax({
            type: 'POST',
            url: '<?php echo $_SERVER['PHP_SELF']; ?>',
            data: { myid: 123456 },
            success: function(data) {
                alert("Transaction Completed!");
            }
        });
    }}
</script>
<?php if ($_POST['myid']) { echo $_POST['myid']; } ?>

The callback function seems to be working fine, as I have tested it. However, I am facing problems with the execution of the ajax post and cannot see any output from the PHP echo.

Any suggestions or ideas on what might be going wrong?

Thank you for your assistance.

Edit: I made some changes to the script, specifically at the point where the AJAX request is being sent successfully. Despite this, I still cannot get the PHP section to display any output.

phpjavascriptajax

Answer №1

In the event that the AJAX-Call is currently successful, you cannot simply use PHP to echo anything. The information is transmitted to the client, but PHP is only interpreted on the server side. As a result, no HTTP-Request is being sent anymore (which is essentially the purpose of an AJAX-Call) and PHP does not execute any actions at this stage.

To display your new content on the page, you need to utilize JavaScript to add it to the DOM. Give this method a try and observe if the message appears on your webpage. In my example, I am appending it to the body because I lack knowledge about your Markup and the data you receive:

     $.ajax({
                type: 'POST',
                url: '<?php echo $_SERVER['PHP_SELF']; ?>',
                data: { myid: 123456 },
                success: function(data) {
                    alert("Transaction Completed!");
                    $('body').prepend('<p>AJAX-Call Successful</p>');
                }
            });

Afterwards, you can inspect the data-variable by using console.log(data), access the returned data, and make modifications to the DOM through JavaScript.

Answer №2

Alright, let's begin.

writeback("Transaction Successful!");

To address the issue:

writeback("Transaction Completed!");

Answer №3

  1. There is a minor syntax error in your code where you have a trailing comma after the number 123456.

    data: { myid: 123456, },

  2. Another issue in your code is that you forgot to include a closing } for your callback function.

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